Board Thread:Off-Topic Posts/@comment-32576568-20190405202604/@comment-36963837-20190411222732

Crystal math.

I don’t know why the hell it slipped my mind that imaginary numbers only come with the radicals DLC.

Excuse my retardation

-3^3=-1•3•3•3=-1•27=-27; (-3)^3=-27; ignore my bullshitery

yet

This still doesn’t work;


 * 1) 3^3+2^3-1^3=27+8-1=34>33; variable c must be greater than 1.
 * 2) 3^3+2^3-2^3=3^3=27<33; variable c cannot subtract variable b, thus variable c must be less than 2; since neither fit variable b must be greater than 2.
 * 3) 3^3+3^3-2^3=27+27-8=36>33; variable c must be greater than 2, yet since exceeding this would be canceling both variable b and c, leaving only a (where it is impossible for a to equal 33 as a whole number), no.
 * 4) as 3^3 (27) is the highest variable replacement, there cannot be further subtraction within the expression.

Conclusion: it’s still improbable for whole numbers to exist, so solve my atomic structure problem.